Assembly - Add 2 interger number

Using AT&T syntax. First, is integer to string. We will divide 10 and push remainderto stack. Finish when result by 0. Pop from stack, and add 48 to convert to ascii charater. Now, you can print number:
.data
a:
.int 123
b:
.int 10
c:
.int 0
thuong:
.int 0
du:
.int 0
Enter:
.int 10
s:
.ascii "1"
.text

.globl _start
_start:

#nap so can in vao eax
movl a,%eax
movl $0,%ecx

#tach so
tach:
movl $0,%edx

#chia cho 10
divl b

#push so du vao
addl $48,%edx
pushl %edx
inc %ecx
cmp $0,%eax
jne tach

in:
popl %eax

#luu ecx
movl %ecx,c

#in
movl %eax,du
movl $4,%eax
movl $1,%ebx
movl $du,%ecx
movl $1,%edx
int $0x80

#tra ecx
movl c,%ecx
loop in

exit:
movl $1,%eax
movl $0,%ebx
int $0x80

Soure: http://www.mediafire.com/?m8hzcrvum926878

And full source to print negative number: http://www.mediafire.com/?72h14t4h30ydf94

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Thanks for reading
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All my Lab:
Linux Lab -- window and Cisco Lab
to be continued - I will update more.

Nam Habach